An electric field of 8.5x10^5 v/m is desired between two parallel plates each of areas 2500 cm^2 and separated by 0.10 mm of air. what charge must be on each plate?

The charge must be on each plate is .

Explanation:

Given that,

Electric field

Area = 2500 cm²

Distance = 0.10 mm

We need to calculate the potential difference

Using formula of potential difference

We need to calculate the capacitor

Using formula of capacitor

Put the value into the formula

We need to calculate the charge

Using formula of charge

Hence, The charge must be on each plate is .

speed of light in vacuum is 300,000 km/s

speed of light in other mediums is given by the expression v = c/n, where c is the speed of light in vacuum and n is the refractive index of medium.

for the first medium v = 200,000 km/s

  so, refractive index of medium = 300000/200000 = 1.5

    1.5 refractive index is usually for glass. so first medium is glass.

for the second medium v = 250,00 km/s

so, refractive index of medium = 300000/250000 = 1.2

    1.2 refractive index is usually for water. so second medium is water.

for the third medium v = 0 km/s

so, refractive index of medium = 300000/0 = ∞

    ∞ refractive index is usually for opaque mediums. so third medium is opaque medium.