It takes 500 j of work to compress a spring 10 cm. what is the force constant of the spring? (b) when a 3.0 kg block is pushed against a massless spring of force constant 4.5. 10' n/m, the spring is compressed 8.0 cm. the block is released and it slides 2.0 m from the point at which it is released across a horizontal surface before friction stops it. what is the coefficient of kinetic friction between the block and the surface?

Explanation:

a) Energy stored in spring = 1/2 k x² = .5 x k 0.1²

500 = 5 x 10⁻³ k ,

k = (500/5) x 10³ = 10⁵ N/m

b )

k = 4.5 x 10¹ = 45 N/m

Stored energy = 1/2 k x² = .5 x 45 x 8² x 10⁻⁴ =1440 x 10⁻⁴ J

This energy gets dissipated by friction .

work done by friction = μ mg d

d is the distance traveled under friction

so 1440 x 10⁻⁴ = μ x 3 x 9.8 x 2

μ = 245 x 10⁻⁴  or 0.00245 which appears to be very small. .

i'm just gonna leave this comment here, so i can get a challange done-

explanation: