Acapacitor has a potential difference of v applied across its plates. if the potential difference across its plates is increased to 2v, the energy stored in the capacitor is: a) reduced to half
b) doubles
c) reduced to one fourth
d) quadruples (four times bigger)
e) none of the above

Option B. doubles

Explanation:

This can be explained by the definition of capacitance that charge on the capacitor will remain constant irrespective of the voltage applied.

This can be given as:

Q ∝ V or Q = CV

where,

Q = charge

V = Voltage

C = Capacitance

So, when V is doubled, C shoul reduce to half to main constant charge on the capacitor:

V' = 2V

C' =

Also , Energy stored in a capacitor, E is given by:

E =                             (1)

Now, when

V' = 2V

C' =

Using eqn (1):

E' =

Energy, E' =

E' = = 2E

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