You connect a 100-resistor, a 800-mh inductor, and a 10.0-uf capacitor in series across a 60.0-hz, 120-v (peak) source. the impedance of your circuit is approximately a) 3772 b) 30222 c) 2652 d) 1002 e) 1072

Impedance, Z = 107 ohms

Explanation:

It is given that,

Resistance, R = 100 ohms

Inductance,

Capacitance,

Frequency, f = 60 Hz

Voltage, V = 120 V

The impedance of the circuit is given by :

...........(1)

Where

is the capacitive reactance,

is the inductive reactance,

So, equation (1) becomes :

Z = 106.26 ohms

or

Z = 107 ohms

So, the impedance of the circuit is 107 ohms. Hence, this is the required solution.

= initial pressure

= final pressure = 2

= initial volume

= final volume = /4

= initial temperature = 20 c = 20 + 273 = 293 k

= final temperature = ?

using the equation