Physics, 20.08.2019 20:30, king845

According to the de broglie relation, the wavelength of a "matter" wave is inversely proportional to the momentum of the particle.

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Physics, 27.06.2019 08:20, TrueKing184

To understand de broglie waves and the calculation of wave properties.in 1924, louis de broglie postulated that particles such as electrons and protons might exhibit wavelike properties. his thinking was guided by the notion that light has both wave and particle characteristics, so he postulated that particles such as electrons and protons would obey the same wavelength-momentum relation as that obeyed by light: λ=h/p, where λ is the wavelength,p the momentum, and h planck's constant.part afind the de broglie wavelength λ for an electron moving at a speed of 1.00×106m/s. (note that this speed is low enough that the classical momentum formula p=mv is still valid.) recall that the mass of an electron isme=9.11×10−31kg, and planck's constant is h=6.626×10−34j⋅s.express your answer in meters to three significant figures.part bfind the de broglie wavelength λ of a baseball pitched at a speed of 40.6 m/s . assume that the mass of the baseball is 0.143kg.express your answer in meters to three significant figurespart cconsider a beam of electrons in a vacuum, passing through a very narrow slit of width 2.00μm. the electrons then head toward an array of detectors a distance 1.087 m away. these detectors indicate a diffraction pattern, with a broad maximum of electron intensity (i.e., the number of electrons received in a certain area over a certain period of time) with minima of electron intensity on either side, spaced 0.511 cm from the center of the pattern. what is the wavelength λ of one of the electrons in this beam? recall that the location of the first intensity minima in a single slit diffraction pattern for light is y=lλ/a, where l is the distance to the screen (detector) and a is the width of the slit. the derivation of this formula was based entirely upon the wave nature of light, so by de broglie's hypothesis it will also apply to the case of electron waves.express your answer in meters to three significant figures.

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Physics, 19.07.2019 17:00, dennismathews01

According to de broglie, as the momentum of a moving particle is tripled, the corresponding wavelength changes by what factor?

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Physics, 23.07.2019 06:00, LoserMcBadface

The wavelength and energy of a wave are inversely proportional. based on this, which wave listed would have the lowest energy. a) wave with wavelength of 600 m b) wave with wavelength of 600 cm c) wave with wavelength of 600 mm d) wave with wavelength of 600 km

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Physics, 07.09.2019 00:30, zionboy77

De broglie postulated that for a particle with a momentum p, its corresponding wavelength is λ = n, where h is the planck's constant. assuming that a particle has a mass of m and a total kinetic energy of e, express the de broglie wavelength of this particle as a function of e, m, and h only. (ii) given that f(x) [in(5x2)]6, then determine the value of f'(2).

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