Two sources of light of wavelength 686 nm are separated by a horizontal distance x. they are 3 m from a vertical slit of width 0.5 mm. what is the least value of x for which the diffraction pattern of the sources can be resolved by rayleigh's criterion?

X = 5.48 mm

Explanation:

for single slit

By Rayleigh criterian

where d = slit width =0.5 mm

wavelength

therefore maximum of value of X can be  calculated from above

X = 5.48 mm

no. bullets are macro objects. wave nature is for light waves, extremely tiny particles. if a light particle was the size of your finger, the bullet would be the size of the universe. so basically, that huge difference in size makes the wave nature of matter insignificant.