Acar travels at 2000 meters east in 40 seconds. what is the cars velocity

50 ms⁻¹

Explanation:

Given that,

Distance Travelled =2000 meters

Time Taken =40 seconds

velocity = ?

we know,

velocity = Distance  / Time

              =(2000 /  40) ms⁻¹

               =50 ms⁻¹

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s