Physics, 18.08.2019 03:20, genyjoannerubiera

Two cars start from rest at a red stop light. when the light turns green, both cars accelerate forward. the blue car accelerates uniformly at a rate of 3.7 m/s2 for 4.5 seconds. it then continues at a constant speed for 8.6 seconds, before applying the brakes such that the carâs speed decreases uniformly coming to rest 229.73 meters from where it started. the yellow car accelerates uniformly for the entire distance, finally catching the blue car just as the blue car comes to a stop.(a) how fast is the blue car going 3.6 seconds after it starts? (b) how fast is the blue car going 8.8 seconds after it starts? (c) how far does the blue car travel before its brakes are applied to slow down?

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answered: franklinkaylieg3873

(a)13.32m/s

(b)16.65m/s

Explanation:

Given

blue car starts from rest and accelerate for 4.5 sec at 3.7 m/s^2

then runs at a constant velocity for 8.6 sec and finally decelerate to come at rest.

total distance(s)=229.73

(a)Velocity of blue car after 3.6 sec

v=u+at

here u(initial velocity )=0

v=0+(3.7)3.6=13.32 m/s

(b)Given car accelerate for 4.5 sec and after that it runs at constant velocity therefore velocity of car after 8.8 sec will equal to velocity of car after 8.6 sec

v=u+at

v=0+(3.7)4.5=16.65 m/s

(c)Distance traveled by blue car before brake is applied

let S_1 be the distance traveled during acceleration of car and s_2 be the distance traveled during constant velocity

$S_1=ut+\frac{1}{2}at^2$

here u=0

$S_1=\farc{1}{2}(3.7)(4.5)^2$ =37.4625m

$S_2=vt+\frac{1}{2}at^2$

here v=16.65 m/s a=0

S_2 =16.65(8.6)=143.19 m

Thus total distance= S_1+S_2 =180.6525 m

answered: Guest

Velocity is the speed of an object in a certain direction so you'd need to know speed and direction

answered: Guest

m₁v₁ + m₂v₂ = (m₁ + m₂)vmomentum is conserved.the left-hand side of the equation represents the momentum in the system before the collision.the right-hand side represents the momentum in the system after the collisionm₁ and v₁ represents the mass and the velocity of the physics blockm₂ and v₂ represents the mass and velocity of the ball of puttyv represents the final velocity of the combined mass.the question states the two masses stick together. they combined mass has its own velocity with the body mass the sum of the two objects' massestheir combined momentum is (m₁ + m₂)vto find the magitude of (m₁ + m₂)v, we need to add the vectors on the left-hand side of the equation: m₁v₁ + m₂v₂.note the diagram. i have positioned the vectors in accordance with their directions.the magnitude of the resultant can be calculated using the pythagorean theorem since this is a right triangle situation (north and west are perpendicular)|(m₁ + m₂)v| = √[ (m₁v₁)² + (m₂v₂)² ]|(m₁ + m₂)v| = √[ (1.5kg·8.0m/s)² + (0.40kg·20m/s)² ]|(m₁ + m₂)v| = 14.4 kg m/sfor two significant figures (assuming that 20m/s is two), this rounds to 14 kg m/s

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Two cars start from rest at a red stop light. when the light turns green, both cars accelerate forwa...