Physics, 13.08.2019 02:10, haza1873

The secondary coil of a step-up transformer provides the voltage that operates an electrostatic air filter. the turns ratio of the transformer is 46: 1. the primary coil is plugged into a standard 120-v outlet. the current in the secondary coil is 1.8 x 10-3 a. find the power consumed by the air filter.

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answered: hannahv10

The power consumed by the air filter is 9.936 watts

Explanation:

It is given that, the secondary coil of a step-up transformer provides the voltage that operates an electrostatic air filter.

Turn ratio of the transformer, $\dfrac{N_s}{N_p}=\dfrac{46}{1}$

Voltage of primary coil, $V_p=120\ V$

Current in the secondary coil, $I_s=1.8\times 10^{-3}\ A$

The power consumed by the air filter is :

$P_s=I_s\times V_s$ ...........(1)

For a transformer, $\dfrac{N_s}{N_p}=\dfrac{V_s}{V_p}$

So, $P_s=I_s\times (\dfrac{N_s}{N_p})\times V_p$

$P_s=1.8\times 10^{-3}\times (\dfrac{46}{1})\times 120$

$P_s=9.936\ Watts$

So, the power consumed by the air filter is 9.936 watts. Hence, this is the required solution.

answered: Guest

graphing motion: mastery test

209be

what is the instantaneous acceleration of

the particle at point b?

0 meters/second?

10 meters/second?

12 meters/second?

velocity imetersisecond

15 meters/second?

time (seconds)

answer: 0 meters/second^2

answered: Guest

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The secondary coil of a step-up transformer provides the voltage that operates an electrostatic air...