An rlc series circuit consists of a 50 ω resistor, a 200 μf capacitor, and a 120-mh inductor whose coil has a resistance of 20 ω. the source for the circuit has an rms emf of 240 v at a frequency of 60 hz. calculate the rms voltages across the inductor.

182.9 Volts

Explanation:

R = resistance of the resistor = 50 Ω

C = capacitance of the capacitor = 200 μF = 200 x 10⁻⁶ F

L = Inductance of the inductor = 120 mH = 0.12 H

f = frequency = 60 Hz

Capacitive reactance is given as

X = (2πfC)⁻¹

X = (2(3.14) (60) (200 x 10⁻⁶))⁻¹

X = 13.3 Ω

Inductive reactance is given as

X' = 2πfL

X' = 2(3.14) (60) (0.12)

X' = 45.2 Ω

Impedance of the circuit is given as

z = √(R² + (X' - X)²)

z = √(50² + (45.2 - 13.3)²)

z = 59.31 Ω

V = rms emf of the source = 240 Volts

rms voltage across the inductor is given as

V' = V z⁻¹ X'

V' = (240) (59.31)⁻¹ (45.2)

V' = 182.9 Volts

learn it on the intertant so you can solve

the answer is the first electromagnet (a). this is because it has more coils around the ferromagnetic material. increasing the number of coils increases the surface area in which the metal interacts with the current in the coil. this enables more atoms in the metal to become aligned hence becoming more magnetized.