Avery big hockey puck with mass 2.5 kg traveling 20 degrees north of east at 10.0 m/s strikes a puck with a mass of 4.0 kg traveling north at 2 m/s. the 2.5 kg puck exits the collision in a direction that is 30 deg. north of east at a velocity of 8.0 m/s. what is the magnitude and direction of the 4.0 kg puck's velocity?

Velocity = 0.47 m/s

Direction = 65 degrees South of east.

(295 degrees counter clockwise from + X axis).

Explanation:

Conservation of momentum along the X and Y directions can be used to determine the velocity of the 4 kg puck.

Along the X direction momentum conservation is as follows:  

2.5 cos 20 + 4.0 cos 90 = 2.5 cos 30 + 4 v cos α

⇒  v cos α = 2.5 ( cos 20 - cos 30) ÷ 4 = 0.46 m/s

2.5 sin 20 + 4 sin 90 = 2.5 sin 30 + 4 v sin α

v sin α = (2.5 sin 20 - 2.5 sin 30) ÷ 4 =  -0.0987 m/s

v = √(v² cos² α + v² sin² α) = √ (0.46² + (-0.0987)² = 0.47 m/s

Direction = α = tan⁻¹ (-0.0987/0.46) = -65 degrees = 65 degrees clock wise from +X axis or 295 degrees counter clockwise from +X axis

this is an example of "committed" time.

committed time, as contracted time, takes need over essential and available time since it is seen as profitable work. it alludes to the time allotted to keep up a home and family. at the point when a man is commuting using committed time this individual may feel that the drive is an obligation to family, for example, strolling youngsters to class or driving a mate to work. contracted and committed time clients may feel that their commute could really compare to the commute of important or leisure time clients on the grounds that their commute is profitable work. in this manner, they might be more disposed to pick a mechanized method of movement.  

there are no atoms