The enthalpy of fusion of ice is 330,000 j/kg. if i have a 1 kg sample, how much energy is needed to melt all of it?
a. 33,000 j
b. 3,300 j
c. 330,000 j
d. 330 j

C. 330,000 J

Explanation:

Latent heat = mass × specific latent heat

q = mL

Given m = 1 kg and L = 330,000 J/kg:

q = (1 kg) (330,000 J/kg)

q = 330,000 J

C. 330,000 J

Explanation:

The enthalpy of fusion of ice is 330,000 J/kg. If someone has a 1 kg sample, they will need 330,000 J energy in order to melt all of it.

(1 kg) (330,000 J/kg)

1= 26.17

2= 1.17

3=30.86

4=5.86

just took the assigment on edge