An object of mass m = 5.0 kg hangs from a cord around a light pulley: the length of the cord between the oscillator and the pulley is l = 2.0 m. when the oscillator is set to a frequency of 150 hz, a standing wave with six loops is formed. what must be the linear mass density of the cord?
Answers: 1
is the length of the string and 
the velocity of propagation. Use this expression to find the value of 
is the desirable variable of the problem, the linear mass density, and 
is the tension of the cord. The tension is equal to the weight of the mass hanging from the cord:
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An object of mass m = 5.0 kg hangs from a cord around a light pulley: the length of the cord betwee...
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