A50kg driver sits stopped at a traffic light. another car rear-ends her and causes her to accelerate at 20m/s^2. it all occurs in 0.35s. a) what is the impulse given to the driver? b) what is the average force exerted on the driver and c) what exerts the force? show work

your answer is c! hope this : )

well clustered together.

points close on a scatter diagram

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft