On an inclined plane with angle α to the horizontal it leans a rod which, due to a guide, it can move only vertically. find the velocity "u" with which will climb the rod when the inclined plane is moved to the left with the constant velocity "v".
v, alpha

u=?
me with explanations and a draw i don't get it when in decomposition of "u" what vector it will have the value = value of v and i don't know how to recognize the alpha angle in the decomposition.

u = - tan * v

Explanation:

Here is a different perspective. An observer that moves along the incline has a velocity w. The velocity v of the incline is equal to the horizontal componant of the observer with the opposit sign. The velocity u of the rod is the vertical component of the observer.

You get the following equations:

u = w sin

v = - w cos

Dividing both equations give:

u/v = -tan

u = - tan * v

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your question asks at which segment does freezing occur.

since we're talking about water, the freezing point of water will be 32 degrees fahrenheit or below.

hope this ! ~

a.   mass number from atomic number