Asquirrel jumps into the air with a velocity of 4m/s at an angle of 40°. what is the maximum height reached by the squirrel?

0.336 m

Explanation:

This situation is a good example of the parabolic motion, in which the travel of the squirrel has two components: x-component and y-component. Being their main equations as follows:

x-component:

  (1)

  (2)

Where:

is the squirrel's initial speed

is the angle at which the squirrel jumps into the air

is the time since the bullet is shot until it hits the ground

y-component:

  (3)

  (4)

Where:

 is the initial height of the squirrel

 is the final height of the squirrel (when it finally hits the ground)

 is the acceleration due gravity

Now, we have to find the maximum height reached by the squirrel, and this happens when . So equation (2) is rewritten as:

 (5)

 (6)

 (7)

Solving (7):

 (8)

 (9)

Substituting the value of (9) in (3):

  (10)

Finally:

  (11)

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer