William burns 5.1 g of peanuts beneath 1000 g of water, which increases in temperature from 28◦c to 47◦c. assuming 50% efficiency, what is the food value of the peanut? answer in units of cal

food value of the peanut is 38 000 cal

Explanation:

Heat observed by water

C is a constant.

For water,  C = 1 c gm/ °C

So here Q = (1000) (1 ) (47-28)  

Q = 19 000 cal  

FOR  50% efficiency,

Total  heat released by peanut is:  

19,000 cal / 0.50 = 38 000 cal  

So the food value of the peanut is 38 000 cal.  

a charge 3q is at the origin, and a charge −2q is on the positive x axis at x=a. part a where on the x-axis would you place a third charge so it would experience no net electric force? enter an expression for the exact answer, which will involve a square-root sign. (do not enter an approximate decimal answer.)