The fundamental (latex: n=1 n = 1 harmonic or mode) frequency created on a stretched string with fixed ends occurs when the string is driven at a frequency of 50 hz. if the tension in this string is doubled without changing its mass density, what would be the new fundamental frequency?

Explanation:

Given

Fundamental Frequency(f) is 50 Hz

and frequency is given by

Where T= tension

=mass per unit length

if tension is doubled

Divide 1& 2

if the person is shown to have +90n, then ans is -10n.

if the person is shown to have -90n, then ans is +10n.

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

where is unknown. because the position is parabolic, there is symmetry about the midpoint at , and we know that

so that the position function is

which means the velocity is

then the total distance traveled is

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at and ends at , so its displacement is 0.