Apotential difference of 3.10 nv is set up across a 2.09 cm length of copper wire that has a radius of 2.32 mm. how much charge drifts through a cross section in 3.05 ms? assume that the resistivity of copper is 1.69 × 10-8 ω·m.

drift change  = 4.5241 × 10^-7 C

Explanation:

Given data

potential difference = 3.10 nV

length= 2.09 cm

radius = 2.32 mm

to find out

charge drifts through a cross section in 3.05 ms

solution

we will apply here  drift change formula that is

drift change = potential difference × π × radius² × time / resistance × length

put all the value and we get drift change

drift change = 3.10 × 10^-9 × π × (0.00232)² × 3.05× 10^(-3) / 1.69×10^(-8) × 0.0209

drift change  = 4.5241 × 10^-7 C

= initial pressure

= final pressure = 2

= initial volume

= final volume = /4

= initial temperature = 20 c = 20 + 273 = 293 k

= final temperature = ?

using the equation