Aproton is released from rest at the positive plate of a parallelplatecapacitor. it crosses the capacitor and reaches the negativeplate with a speed of 50,000 m/s. what will be the final speed ofan electron released from rest at the negative plate

2.1406 × m/sec

Explanation:

we know that energy is always conserved

so from the law of energy conservation

here V is the potential difference  

we know that mass of proton = 1.67× kg

we have given speed =50000m/sec

so potential difference

now mass of electron =9.11×

so for electron

so the velocity of electron will be 2.1406× m/sec