Abeam of light is incident from air on the surface of a liquid. if the angle of incidence is 25.5° and the angle of refraction is 15.6°, find the critical angle for the liquid when surrounded by air.

Фc = 38.66°

Explanation:

from Snell's law:

n1×sin(Ф1) = n2×sin(Ф2)

for air, n1 = 1.0

1.0×sin(Ф1) = n2×sin(Ф2)

n2 = 1.0×sin(Ф1)/sin(Ф2)

n2 = 1.0×sin(25.5)/sin(15.6) = 1.601

For the critical angle: Ф2 = 90° and n2 = 1.601

n2×sin(Фc) = n1×sin(Ф2) = n1

sin(Фc) = n1/(n2×sin(Ф2))

sin(Фc) =  (1.0)/(1.601×sin(90))

sin(Фc) = 0.625

      Фc = 38.66°

Therefore, the critical angle is 38.66°

answer: what are you talking about?

explanation:

what experimental evidence led scientists to change from the previous model to this one?

a few of the positive particles aimed at a gold foil seemed to bounce back.

the colors of light emitted from heated atoms had very specific energies.

experiments with water vapor showed that elements combine in specific proportions.

cathode rays were bent in the same way whenever a magnet was brought near them.