Atransformer connected to a 120-v (rms) ac line is to supply 13,000 v (rms) for a neon sign. to reduce shock hazard, a fuse is to be inserted in the primary circuit; the fuse is to blow when the rms current in the secondary circuit exceeds 8.50 ma. what current rating should the fuse in the primary circuit have?

The current is 0.921 A.

Explanation:

Given that,

Voltage = 120 V

Current = 13000

Current exceeds = 8.50 mA

We need to calculate the current rating

Using relation of current and voltage

.....(I)

Where, = current in primary circuit

= current in secondary circuit

= voltage in primary circuit

= voltage in primary circuit

Put the value into the formula

Hence, The current is 0.921 A.

scattering of light by tiny particles in air to produce the colors we see on sky, is dependent on the following factors:

(i) wavelength of light

(ii) size of the scattering particle  

(iii) distance traveled by light through the atmosphere.

according to rayleigh's law of scattering, the amount of scattering is inversely proportional to the fourth power of its wavelength. shorter the wavelength, greater is its scattering. hence violet/blue light is scattered more than red.

sun's light is a composite light ( visible light) with wavelengths in the range 400 nm (violet) to 700 nm (red). as sunlight passes through our atmosphere, the molecules of air scatter light according to their wavelengths. during sunrise and sunset, the sun's position is below the horizon. hence light from the sun travels a greater distance in the atmosphere when compared to its position a noon.

as sunlight enters the earth's atmosphere, blue light is scattered away and at the end of its journey in the sky, only red and orange wavelengths remain in the beam.

hence at sunrise and sunset, the sky appears reddish orange.