A7.25 kg7.25 kg block is sent up a ramp inclined at an angle =28.5°θ=28.5° from the horizontal. it is given an initial velocity =15.0 m/sv0=15.0 m/s up the ramp. between the block and the ramp, the coefficient of kinetic friction is =0.326μk=0.326 and the coefficient of static friction is =0.593.μs=0.593. how far up the ramp in the direction along the ramp does the block go before it comes to a stop

15.03 m

Explanation:

Given:

mass of the block, m = 7.25 kg

Angle, Θ = 28.5°

Initial speed of the block, v₀ = 15 m/s

let the distance traveled by the block be 's'

Now, applying the work energy theorem,

we have

on substituting the values in the above equation, we get

or

or

s = 15.03 m

Hence, the block will travel 15.03 m up the ramp

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