Aproton, traveling with a velocity of 4.5 × 106 m/s due east, experiences a magnetic force that has a maximum magnitude of 8.0 × 10−14 n and a direction of due south. what are the magnitude and direction of the magnetic field causing the force?

Magnetic field, B = 0.11 i (in k direction)

Explanation:

It is given that,

Velocity of the proton,

Magnetic force, (due south)

The magnetic force acting on the electron is given by :

(-j) = (i) × (B)

q is the charge on proton

B = 0.11

So, the magnitude of 0.11 T is acting on the proton in and is acting directed upward above the plane. Hence, this is the required solution.

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.