Alight bulb emits light uniformly in all directions. the average emitted power is 150.0 w. at a distance of 5 m from the bulb, determine (a) the average intensity of the light, (b) the rms value of the electric field, and (c) the peak value of the electric field.

a) 0.477 W/m²

b) 13.407 N/C

c) 18.96 N/C

Explanation:

P = Power = 150 W

r = Distance = 5 m

ε₀ = Permittivity of space = 8.854×10⁻¹² F/m

a) Average intensity

∴ Average intensity is 0.477 W/m²

b) Rms value

∴ Rms value of the electric field is 13.407 N/C

c) Peak value

∴ Peak value of the electric field is 18.96 N/C

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b.

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