At noon on a clear day, sunlight reaches the earth's surface at madison, wisconsin, with an average intensity of approximately 1.00 kj·s−1·m−2. if the sunlight consists of photons with an average wavelength of 510.0 nm, how many photons strike a 8.90 cm2 area per second?

2.282 ×  photons strike

Explanation:

Given data

average intensity = 1.00 kJ·s−1·m−2

wavelength = 510.0 nm

area = 8.90 cm²

to find out

how many photons strike

solution

we know energy of 1 photon i.e

= hc/ wavelength = 6.626 × × 3 / 510

energy of 1 photon = 3.9 × J

so now we know no of joules hitting is 8.90 cm²/sec

i.e = 1.00 kJ × 8.90 cm²

= 1000 × 8.90

= 0.8900 J

so number of photon is

N = 0.8900 / 3.9 ×

N = 2.282 ×

2.282 ×  photons strike

it may be wrong but i think its a