Physics
Physics, 31.07.2019 21:30, certifiedtino4576

In the two-slit experiment, monochromatic light of frequency 5.00 × 1014 hz passes through a pair of slits separated by 2.20 × 10-5 m. (c = 3.00 × 108 m/s) (a) at what angle away from the central bright spot does the third bright fringe past the central bright spot occur? (b) at what angle does the second dark fringe occur?

answer
Answers: 1

Other questions on the subject: Physics

image
Physics, 22.06.2019 17:40, yoongnzl
Aspring is used to stop a 50-kg package which is moving down a 20º incline. the spring has a constant k = 30 kn/m and is held by cables so that it is initially compressed 50 mm. knowing that the velocity of the package is 2 m/s when it is 8 m from the spring and neglecting friction, determine the maximum additional deformation of the spring in bringing the package to rest.
Answers: 1
image
Physics, 22.06.2019 20:00, teescub9738
In an old-fashioned amusement park ride, passengers stand inside a 3.0-m-tall, 5.0-m-diameter hollow steel cylinder with their backs against the wall. the cylinder begins to rotate about a vertical axis. then the floor on which the passengers are standing suddenly drops away! if all goes well, the passengers will “stick” to the wall and not slide. clothing has a static coefficient of friction against steel in the range 0.60 to 1.0 and a kinetic coefficient in the range 0.40 to 0.70. part a what is the minimum rotational frequency, in rpm, for which the ride is safe? express your answer using two significant figures. f f = rpm
Answers: 1
image
Physics, 23.06.2019 01:30, kris1920
When a lead acid car battery is recharged by the alternator, it acts essentially as an electrolytic cell in which solid lead(ii) sulfate is reduced to lead at the cathode and oxidized to solid lead(ii) oxide at the anode. suppose a current of is fed into a car battery for seconds. calculate the mass of lead deposited on the cathode of the battery.
Answers: 3
image
Physics, 23.06.2019 10:10, Jperez6541
Now that we have a feel for the state of the circuit in its steady state, let us obtain the expression for the current in the circuit as a function of time. note that we can use the loop rule (going around counterclockwise): e−vr−vl=0. note as well that vr=ir and vl=ldidt. using these equations, we can get, after some rearranging of the variables and making the subsitution x=er−i, dxx=−rldt. integrating both sides of this equation yields x=x0e−rt/l. use this last expression to obtain an expression for i(t). remember that x=er−i and that i0=i(0)=0. express your answer in terms of e, r, and l. you may or may not need all these variables. use the notation exp(x) for ex.
Answers: 1
Do you know the correct answer?
In the two-slit experiment, monochromatic light of frequency 5.00 × 1014 hz passes through a pair of...

Questions in other subjects:

Konu
World Languages, 09.06.2021 20:30