Astudent is told to use 20.0 g of sodium chloride to make an aqueous solution that has a concentration of 10.0 g/l (grams of sodium chloride per liter of solution). assuming that 20.0 g of sodium chloride has a volume of 7.50 ml, show that she will need about 1.99 l of water to make this solution. in making this solution, should she add the solute to the solvent or the solvent to the solute?

Explanation:

Concentration of sodium chloride = 10.0 g/L

1 Liters of solution has 10 g of sodium chloride

The volume of solution in which 20 g of sodium chloride will present is:

Volume of solution we will be making is of 2 L.

Volume of 20 g of sodium chloride = 7.50 ml = 0.00750 L

Volume of the water = ?

Volume of solution = Volume of solute + Volume of solvent

Volume of solvent = 2L - 0.00750 L = 1.9925 L

So,volume of water required to prepare the 2 L of 10 g/L solution of sodium chloride is 1.9925 L.

And for while making of the solution , student must add solute the solvent.

hey , the answer is c

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day