Acar of mass 875 kg is traveling 30.0 m/s when the driver applies the brakes, which lock the wheels. the car skids for 5.60 s in the positive x - direction before coming to rest. (a) what is the car’s acceleration? (b) what magnitude force acted on the car during this time? (c) how far did the car travel?

Explanation:

It is given that,

Mass of the car, m = 875 kg

Initial speed of the car, u = 30 m/s

Brakes are applied i.e. v = 0

The car skids for 5.60 s in the positive x - direction before coming to rest, t = 5.6

(a) Acceleration of the car,

(b) Force, F = ma

F = -4681.25 N

So, the force of 4681.25 N is acting on the car.

(c) Let x is the distance covered by the car. So,

x = 84.11 meters

So, the distance covered by the car is 84.11 meters. Hence, this is the required solution.

its a 5.5 n

glad that

t = 1/400 h   ⇔ 0.0025 h ⇔ 9s ⇔ 0.15 m

any of the answers are correct.