Alarge fish with a mass of 3.65kg moving with an initial velocity of 5.0 m/s grabs a smaller fish with a mass of 1.30 kg. if the smaller fish was moving in the same direction as the larger fish at a speed of 2.5 m/s before he was eaten, what is the velocity of the two fish after impact?

Explanation:

m1= 3.65kg

v1= 5 m/s

m2= 1.3 kg

v2= 2.5 m/s

V=?

m1*v1 + m2*v2 = (m1+m2) * V

V= (m1*v1 + m2*v2) / (m1+m2)

V= 4.34 m/s

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.

option number c is the right answer.