The a string on a violin has a fundamental frequency of 440 hz. the length of the vibrating portion is 32 cm, and it has mass 0.35 g. under what tension must the string be placed?

86.75 N

Explanation:

f = 440 Hz

l = 32 cm = 0.32 m

m = 0.35 g = 0.35 x 10^-3 kg

μ = m / l = 0.35 x 10^-3 / 0.32 = 1.094 x 10^-3 kg/m

The formula for the fundamental frequency is given by

Where, T be the tension

T = 86.75 N

Thus, the tension in the string is 86.75 N.

b. a lightning bug, plug of grass, and a worm