At what distance from the central axis of a long straight thin wire carrying a current of 5.0 a is the magnitude of the magnetic field due to the wire equal to the strength of the earth's magnetic field of about 5.0 × 10-5 t?

The magnetic field at a given distance from a very long (essentially infinitely long) current-carrying wire is given by:

B = μ₀I/(2πr)

B = magnetic field strength, μ₀ = magnetic constant, I = current, r = distance from wire

Given values:

B = 5.0×10⁻⁵T, μ₀ = 4π×10⁻⁷H/m, I = 5.0A

Plug in and solve for r:

5.0×10⁻⁵ = 4π×10⁻⁷(5.0)/(2πr)

r = 0.02m

the small 0.38-kg slider is known to move from position a to position b along the vertical-plane slot. determine (a) the work done on the body by its weight and (b) the work done on the body by the spring. the distance r = 0.70 m, the spring modulus k = 154 n/m, and the unstretched length of the spring is 0.53 m

explanation:

-reverse card

conduction, convection, radiation