The protein calcineurin binds to the protein calmodulin with an association rate of 8.9 3 103 m21s21 and an overall dissociation constant, kd, of 10 nm. calculate the dissociation rate, kd, including appropriate units.

K(dissociation) = 8.93 × 10 ⁻⁵ s⁻¹

Explanation:

Given data :

The association rate, K(association) = 8.93 × 10 ³ M⁻¹. s⁻¹

The value of the overall dissociation constant is, Kd = 10 nM = 10 × 10⁻⁹ M

Now,

The dissociation constant (Kd) is given as:

Kd = K(dissociation)/K(association)

on substituting the values, we get

10 × 10⁻⁹ M = K(dissociation) /8.93 × 10 ³ M⁻¹. s⁻¹

or

K(dissociation) = 8.93 × 10 ⁻⁵ s⁻¹

i would say the answer is food.

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