problem 1.5 a 250 g sample at 80°c is placed in a calorimeter containing 300 g of water. the mass of the aluminum calorimeter cup is 100 g. the initial temperature of the water and cup is 20.0°c, and the final temperature is 21.8°c. what is the specific heat of the sample?

0.167 J/(g °C)

Explanation:

= mass of the sample = 250 g

= Initial temperature of sample = 80 °C

= mass of the water = 300 g

= mass of the cup = 100 g

= Specific heat of water = 4.186 J/(g °C)

= Specific heat of sample = ?

= Specific heat of aluminum cup = 0.9  J/(g °C)

= Initial temperature of water = 20 °C

= Initial temperature of aluminum cup = 20 °C

= Final temperature = 21.8 °C

Using conservation of heat

Heat lost by sample = Heat gained by water + Heat gained by cup

= 0.167 J/(g °C)

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