The gauge pressure in the tires of your car is 210 kpa (30.5 psi) when the temperature is 25°c (77 °f). several days later it is much colder. use the ideal gas equation of state to estimate the gauge pressure in your tires, when the temperature is 0°c. give your answer both in kilopascals (kpa) and pounds per square inch (psi). (gauge pressure is the difference between absolute pressure and atmospheric pressure, which is ap- proximately 101.3 kpa.)

Under the assumption that the tires do not change in volume, apply Gay-Lussac's law:

P/T = const.

P = pressure, T = temperature, the quotient of P/T must stay constant.

Initial P and T values:

P = 210kPa + 101.325kPa

P = 311.325kPa (add 101.325 to change gauge pressure to absolute pressure)

T = 25°C = 298.15K

Final P and T values:

P = ?, T = 0°C = 273.15K

Set the initial and final P/T values equal to each other and solve for the final P:

311.325/298.15 = P/273.15

P = 285.220kPa

Subtract 101.325kPa to find the final gauge pressure:

285.220kPa - 101.325kPa = 183.895271kPa

The final gauge pressure is 184kPa or 26.7psi.

a, c, d, e are all applying about success strategies.

resonant frequency