An electron is released from rest in a weak electric field given by e =-2.30 x 10-10 n/cj. after the electron has traveled a vertical distance of 1.0 μm, what is its speed? (do not neglect the gravitational force on the electron.) mm/s

Explanation:

It is given that,

An electron is released from rest in a weak electric field of,

Vertical distance covered,

We need to find the speed of the electron. Let its speed is v. Using third equation of motion as :

.............(1)

Electric force is and force of gravity is . As both forces are acting in downward direction. So, total force is:

Acceleration of the electron,

Put the value of a in equation (1) as :

v = 0.010 m/s

So, the speed of the electron is 0.010 m/s. Hence, this is the required solution.

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