Give a rail gun shown below with b-3.0t and rail spacing of 25 cm. a discharging capacitor supplies a current of 100 ka. 5) a. what is the acceleration if the bar has a mass of 0.25 kg. [3 x 10s m/s? ] h. what is the bars speed at the end of a 2.75 m long track [1.2 km/s ]

Explanation:

It is given that,

Magnetic field, B = 3 T

Length of the spacing, L = 25 cm = 0.25 m

Current,

Mass of the bar, m = 0.25 kg

(a) Magnetic force is given by :

F = 75000 N

Using second law of motion,

F = m × a

(B) Let v is the speed of the bars at the end of long track. Initial speed of the bar is 0. Using third equation of motion as :

v = 1284.52 m/s

or

v = 1.2 km/s

So, the speed of the bar at the end is 1.2 km/s. Hence, this is the required solution.