Two point charges of +1.0 μc and -2.0 μc are located 0.50 m apart. what is the minimum amount of work needed to move the charges apart to double the distance between them? (k = 1/4π ε0 = 8.99 × 109 n · m2/c2)

The minimum amount of work needed to move the charges apart to double the distance between them is 0.018 J.

We know to change the position of a charge from one point to another work done can be written as,

Also, we know that the potential energy can be written as,

Given to us

q₁ = +1.0 μC  = 1 x 10⁻⁶ C

q₂ =  -2.0 μC = 2 x 10⁻⁶ C

m

= 0.5 m

Substitute the values,

Hence, the minimum amount of work needed to move the charges apart to double the distance between them is 0.018 J.

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W = 0.018 J

Explanation:

As we know that work done to change the position of charge is given as change in the potential energy of the system

here we can say

so here we have

so we can say

now plug in all values in it

d eras and periods

c) up is the direction the magnetic force is acting on the charge.