Current passes through a solution of sodium chloride. in 1.00 second, 2.68×1016 na+ ions arrive at the negative electrode and 3.92×1016 cl− ions arrive at the positive electrode. what is the current passing between the electrodes? show all your work. express your answer in milliamperes to three significant figures.

10.6 mA

Explanation:

t = time interval = 1.00 s

q = magnitude of charge on each ion = 1.6 x 10⁻¹⁹ C

n₁ = number of Na⁺ ions = 2.68 x 10¹⁶

q₁ = charge due to Na⁺ ions = n₁ q = (2.68 x 10¹⁶) (1.6 x 10⁻¹⁹) = 0.004288 C

n₂ = number of Cl⁻ ions = 3.92 x 10¹⁶

q₂ = charge due to Cl⁻ ions = n₂ q = (3.92 x 10¹⁶) (1.6 x 10⁻¹⁹) = 0.006272 C

i₁ = Current due to Na⁺ ions = = = 0.004288 A

i₂ = Current due to Cl⁻ ions = = = 0.006272 A

Current passing between the electrodes is given as

i = i₁ + i₂

i = 0.004288 + 0.006272

i = 0.01056 A

i = 10.6 x 10⁻³ A

i = 10.6 mA

found in the nucleus

has mass of one amu

ice to water 1 water to vapour 2 latent heat