Abox of mass =21.0 kgm=21.0 kg is pulled up a ramp that is inclined at an angle =21.0∘θ=21.0∘ angle with respect to the horizontal. the coefficient of kinetic friction between the box and the ramp is =0.285μk=0.285 , and the rope pulling the box is parallel to the ramp. if the box accelerates up the ramp at a rate of =2.09 m/s2a=2.09 m/s2 , calculate the tension in the rope. use =9.81 m/s2g=9.81 m/s2 for the acceleration due to gravity.

The tension of the rope is T= 172.52 N

Explanation:

m= 21 kg

α= 21º

μ= 0.285

a= 2.09 m/s²

g= 9.81 m/s²

W= m*g

W=206.01 N

Fr= μ*W*cos(α)

Fr= 54.81 N

Fx= W * sin(α)

Fx= 73.82 N

T-Fr-Fx = m*a

T= m*a + Fr + Fx

T= 172.52 N

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