The force exerted by the wind on the sails of a sailboat is 390 n north. the water exerts a force of 180 n east. if the boat (including its crew) has a mass of 270 kg, what are the magnitude and direction of its acceleration?

1.59 m/s^2, 65.2°

Explanation:

F1 = 390 N North

F2 = 180 N east

m = 270 kg

Net force is the vector sum of both the forces.

F = 429.53 N

Direction of force

tan∅ = F1 / F2 = 390 / 180 = 2.1667

∅ = 65.2°

The direction of acceleration is same as the direction of net force.

The magnitude of acceleration is

a = F / m = 429.53 / 270 = 1.59 m/s^2

what was the acceleration of the 2 kg cart?

⇒ 16.0 cm/s2

what was the acceleration of the 4 kg cart?

⇒ 8.1 cm/s2

what was the acceleration of the 6 kg cart?

⇒ 5.3 cm/s2

at positions a, g kinetic energy is maximum.

at position d, potential energy is maximum.