An electron with a speed of 1.9 × 107 m/s moves horizontally into a region where a constant vertical force of 4.9 × 10-16 n acts on it. the mass of the electron is 9.11 × 10-31 kg. determine the vertical distance the electron is deflected during the time it has moved 24 mm horizontally.

Explanation:

It is given that,

Speed of the electron in horizontal region,

Vertical force,

Vertical acceleration,

..........(1)

Let t is the time taken by the electron, such that,

...........(2)

Let is the vertical distance deflected during this time. It can be calculated using second equation of motion:

u = 0

So, the vertical distance the electron is deflected during the time is 0.426 mm. Hence, this is the required solution.

unbalanced force

explanation:

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft