At 900.0 k, the equilibrium constant (kp) for the following reaction is 0.345. 2so2(g)+o2(g)→2so3(g) at equilibrium, the partial pressure of so2 is 30.6 atm and that of o2 is 13.9 atm. the partial pressure of so3 is atm.

Answer : The partial pressure of is, 67.009 atm

Solution :  Given,

Partial pressure of at equilibrium = 30.6 atm

Partial pressure of at equilibrium = 13.9 atm

Equilibrium constant =

The given balanced equilibrium reaction is,

The expression of will be,

Now put all the values of partial pressure, we get

Therefore, the partial pressure of is, 67.009 atm

6/12=1/2

step-by-step explanation:

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