One piece of copper jewelry at 111°c has exactly twice the mass of another piece, which is at 28°c. both pieces are placed inside a calorimeter whose heat capacity is negligible. what is the final temperature inside the calorimeter (c of copper = 0.387 j/g·k)?

83.33 C

Explanation:

T1 = 111 C, m1 = 2m

T2 = 28 C, m2 = m

c  = 0.387 J/gK

Let the final temperature inside the calorimeter of T.

Use the principle of calorimetery

heat lost by hot body = heat gained by cold body

m1 x c x (T1 - T) = m2 x c x (T - T2)

2m x c X (111 - T) = m x c x (T - 28)

2 (111 - T) = (T - 28)

222 - 2T = T - 28

3T = 250

T = 83.33 C

Thus, the final temperature inside calorimeter is 83.33 C.

newton's first law of motion

volts times amps 6 x 0.5 3w