If an object is propelled upward from a height of 128 feet at an initial velocity of 112 feet per second, then its height h after t seconds is given by the equation h equals negative 16 t squared plus 112 t plus 128. after how many seconds does the object hit the ground? round to the nearest tenth of a second.

Explanation:

The equation of motion of an object is given by :

Where

t is the time in seconds

We need to find the time when the object hits the ground. When the object hits the ground, h(t) = 0

So,

On solving above equation using online calculator, t = 8 seconds. So, the object hit the ground after 8 seconds. Hence, this is the required solution.

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