In a simple picture of the hydrogen atom, the electron moves in circular orbits around the central proton attracted by the coulomb force. the lowest (n = 1) energy orbit that is allowed for the electron is at a radius of 5.29 × 10–11 m . calculate the magnetic field strength at the proton due to the orbital motion of the electron in the n = 1 state.

B = 12.46 T

Explanation:

At n = 1 state we know that radius is given as

now we have

here we know that speed is given in that

now the time period is given as

Now the electric current due to revolution of charge is given by

now magnetic field at the center position is given as

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