An ice skater has a moment of inertia of 12 kg-m2 when her arms are outstretched. at this time she is spinning at 2.0 radians/s. if she pulls in her arms and decreases her moment of inertia to 6.0 kg-m2and spins at 4.0 radians/s, how much work does she do to pull her arms in?

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s

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