Three identical uniform meter sticks are placed on the floor. the first stick lies along the y axis from y = 0.510 m to y = 1.51 m. the second stick lies along the x axis from x = 0.210 m to x = 1.21 m. the third stick is positioned so that one end is on the x axis at x = 0.570 m, and the other end is on the y axis at y = 0.822 m. calculate the location of the center of mass of the meter sticks. enter the x position first, then the y position.

Ithink the answer is c but then again i'm probably wrong

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

Inelastic is the answer your looking for.

It maybe because uranus is made of gas but uranus has a solid core in the middle