An ideal gas undergoes isothermal compression from an initial volume of 5.39 m3 to a final volume of 2.84 m3. there is 9.75 mol of the gas, and its temperature is 27.2°c. (a) how much work is done by the gas? (b) how much energy is transferred as heat between the gas and its environment?

a) Work done by gas = -15.584 KJ

b) Energy transferred = 15.584 KJ

Explanation:

Given:

Initial volume of the gas, V₁ = 5.39 m³

Final volume, V₂ = 2.84 m³

Temperature, T = 27.2°C = 273+27.2 = 300.2K

Number of moles, n = 9.75 mol

a) Work done for the given isothermal process is

where, R is the ideal gas constant = 8.31 J/mol.K

substituting the values we get,

or

b) From the first law of thermodynamics

change in internal energy = Heat added - Work done

or,

Now for the isothermal process, ΔU = 0

thus,

or

all of the answers are correct.

falsification is manipulating research materials, equipment, or processes or changing or omitting data or results such that the research is not accurately represented in the research record. plagiarism is the appropriation of another person's ideas, processes, results, or words without giving appropriate credit.

explanation:

fgravity=10x10=100n case 1

fgravity=30x20=600n case 2

6 times more