Light with a wavelength of 310 nm is incident on a metal that has a work function of 3.8 ev. what is the maximum kinetic energy that a photoelectron ejected in this process can have?

3.32×10⁻²⁰ J

Explanation:

Given :

Wavelength of the light λ = 310 nm

work function, W₀ = 3.8 eV

The maximum kinetic energy () is given as:

Where,

h = Planck's constant (6.626 × 10⁻³⁴ Js)

c = speed of light (3 × 10⁸)

also, 1 eV = 1.6 × 10⁻¹⁹ J

substituting the values in the above equation we get

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz